Drawing

What i doing during late in night. I wanted to polish my drawing skill, so i go and search for the anime character and draw it based on the picture. Just hope that It wont be too ugly.

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det (2A) = 2 det(A) is it true?

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det (2A) = 2 det(A) Prove it is true or false. So from above we can see tat the statement is false. However ....... matrix 1x1, [9] Although the general equation is false, but in matrix 1x1 with specific example have proven that the statement is true. So we can conclude that the statement is sometime false.
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爸爸

爸爸，他的手掌有点粗，每天都皱着眉头，拖着疲惫的身躯，每天早出努力赚钱，每天晚归结束一天的活。他从来不埋怨， 可是家里的小孩却常常埋怨 ， 讨厌他那凶恶的脸 ， 讨厌他那么的严厉管教，讨厌他那么的忙。 爸爸，对不起。我们却从来都没为你着想你是那么的累。妈妈在家里选择了温柔的角色所以你只能选择那厉害的角色。在严厉的管教背后不知你为我们流了多少泪，有多么的心痛，多么地心疼当他将手上的藤编挥向我们，教育我们。 爸爸，我错了，我不应该对你大吼大叫，不应该埋怨你为我取的名字，不应该讨厌你每一次就只骂我打我。长大了，我才知道你以往所做的一切都是为了我好。我一点都不谅解你的良苦用心。 爸爸，对不起，我爱你。
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Prove that If det (A) = 1 and all entry (entries) in A is an integer, then all income in A ^ (- 1) is also an integer.

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If det (A) = 1 and all entry (entries) in A is an integer, then all income in A ^ (- 1) is also an integer. Ans: By using the adjoint method to find the inverse of a matrix, we know that A ^ (- 1) = 1 / | A | (adj (A)) and if det (A) = 1 then, A ^ (- 1) = adj (A). The next step is to compute the adjoint matrix of cofactors and cofactor do tansposisi the matrix in which all entry (entries) in A are integers will cause cofactor searched, they also are in the form of an integer. Therefore, all proceeds in A ^ (- 1) is also an integer where A ^ (- 1) = adj (A) after adj (A) is an integer. In short, if det (A) = 1 and all entry (entries) in A is an integer, then all income in A ^ (- 1) is an integer also been proved.
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